Eden Posted November 19, 2009 Report Share Posted November 19, 2009 I recently did a maths assignment and I failed. I'm doing them again, can comeone PLEASE help me? 1. Determine the slopes of the lines with equations: a. 2x-3y=6 b. 3x+y=2 c. y=-2x+1 2. Perpendicular to 3x-4y = 2, passing through (1,2) 3. State the y_intercept of the lines with equations: a. 3x+4y=-8 4. Draw the graphs of: a. y=3x-2 using slope and y intercept b. 3x+y=-6 (I know you couldn't show me on here how to draw rhem (or you could. ahaha), but could you just explain please?) Link to comment Share on other sites More sharing options...
Jen Posted November 19, 2009 Report Share Posted November 19, 2009 I recently did a maths assignment and I failed. I'm doing them again, can comeone PLEASE help me? 1. Determine the slopes of the lines with equations: a. 2x-3y=6 b. 3x+y=2 c. y=-2x+1 2. Perpendicular to 3x-4y = 2, passing through (1,2) 3. State the y_intercept of the lines with equations: a. 3x+4y=-8 4. Draw the graphs of: a. y=3x-2 using slope and y intercept b. 3x+y=-6 (I know you couldn't show me on here how to draw rhem (or you could. ahaha), but could you just explain please?) ^ Well, I've just taken up a maths teaching position, so this will be good practice. I'm happy to work through them with you. Just give me a bit of time to get the setting out and things right and then I'll post them here . Link to comment Share on other sites More sharing options...
Eden Posted November 19, 2009 Report Share Posted November 19, 2009 THANK YOU SO MUCH! My teacher is such a loser and doesn't help me with anything. Link to comment Share on other sites More sharing options...
Jen Posted November 20, 2009 Report Share Posted November 20, 2009 Ok, so here you go. My scanner decided to be a bit annoying and cut off some of the text, but it basically still shows my setting out for most of the questions. I hope this helps at least a little bit. Because I don't know how you were originally taught, it makes it a bit hard to fill in the blanks to see where you are actually having trouble. Page 1 Page 2 Page 3 Page 4 Let me know if you want more/less detail or if there is anything specific you don't get and maybe I can help. Link to comment Share on other sites More sharing options...
flyingwithoutwings Posted November 20, 2009 Report Share Posted November 20, 2009 Oh boy, reading that makes me think of the maths exam I just did. *Shudder* Had I have had something like that, I would've gone a lot better. & Eden, I agree, neither does my maths teacher at times. -__- Funny that you are learning that at the EXACT same time as me, in the exact same way, haha. Link to comment Share on other sites More sharing options...
Barbara Posted December 2, 2009 Report Share Posted December 2, 2009 It's not really homework but it's for a translation I have to make. It's about math. I thought maybe someone could help me. f(x) = sinx => f(x)= 1/sinxf(x) = sinx => f(x)= arcsin x Which one of these functions is the inverse function and how do you call the other function? Link to comment Share on other sites More sharing options...
Emily Posted December 2, 2009 Report Share Posted December 2, 2009 f(x)=arcsin x is the inverse of f(x)=sinx because it maps f(x) back onto the original graph. f(x)=1/sin x is known as the reciprocal as it is a reflection in the line y=x. Hope that makes sense. This website may help explain trigonometric inverse functions: http://www.regentsprep.org/Regents/math/al...inversetrig.htm Link to comment Share on other sites More sharing options...
Slade Posted December 3, 2009 Report Share Posted December 3, 2009 Just following on from what’s mentioned above, f(x) =1/sin(x) is actually called cosecant(x) or cosec(x) for short. Arcsin(x) is the definition of the inverse function of sin(x) as far as I can recall but what it actually means is “the angle whose sin is” or “the angle that has a sin of”. So if sin(x) =1 then arcsin means the angle whose sin is equal to 1 which is 90 degrees. Link to comment Share on other sites More sharing options...
Barbara Posted December 3, 2009 Report Share Posted December 3, 2009 Thank you Emily and Slade. I just needed the names of the functions as I have to translate exam questions. Fortunately, I don't have to answer them. I hated trigonometry. Link to comment Share on other sites More sharing options...
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